[IPython-user] ipython1 and farm tasking

[Brian Granger]

Alex,

First, I would suggest updating your ipython1 install from our svn
repository.  We are about to push out a major new version and the
documentation is _much_ better.  Also, there are many new features
that will hopefully help you.  Here is a simple example (using the
latest svn of ipython1):

In [1]: from ipython1.kernel import client

In [2]: mec = client.MultiEngineClient(('127.0.0.1',10105))

In [3]: tc = client.TaskClient(('127.0.0.1',10113))

In [4]: def fold_package(x):
   ...:     return 2.0*x
   ...:

In [5]: mec.push_function(dict(fold_package=fold_package))
Out[5]: [None, None, None, None]

In [6]: tasks =
[client.Task("y=fold_package(x)",push={'x':x},pull=('y',)) for x in
range(128)]

In [7]: task_ids = [tc.run(t) for t in tasks]

In [8]: tc.barrier(task_ids)

In [9]: task_results = [tc.get_task_result(tid) for tid in task_ids]

In [10]: results = [tr.ns.y for tr in task_results]

In [11]: print results
[0.0, 2.0, 4.0, 6.0, 8.0, 10.0, 12.0, 14.0, 16.0, 18.0, 20.0, 22.0,
24.0, 26.0, 28.0, 30.0, 32.0, 34.0, 36.0, 38.0, 40.0, 42.0, 44.0,
46.0, 48.0, 50.0, 52.0, 54.0, 56.0, 58.0, 60.0, 62.0, 64.0, 66.0,
68.0, 70.0, 72.0, 74.0, 76.0, 78.0, 80.0, 82.0, 84.0, 86.0, 88.0,
90.0, 92.0, 94.0, 96.0, 98.0, 100.0, 102.0, 104.0, 106.0, 108.0,
110.0, 112.0, 114.0, 116.0, 118.0, 120.0, 122.0, 124.0, 126.0, 128.0,
130.0, 132.0, 134.0, 136.0, 138.0, 140.0, 142.0, 144.0, 146.0, 148.0,
150.0, 152.0, 154.0, 156.0, 158.0, 160.0, 162.0, 164.0, 166.0, 168.0,
170.0, 172.0, 174.0, 176.0, 178.0, 180.0, 182.0, 184.0, 186.0, 188.0,
190.0, 192.0, 194.0, 196.0, 198.0, 200.0, 202.0, 204.0, 206.0, 208.0,
210.0, 212.0, 214.0, 216.0, 218.0, 220.0, 222.0, 224.0, 226.0, 228.0,
230.0, 232.0, 234.0, 236.0, 238.0, 240.0, 242.0, 244.0, 246.0, 248.0,
250.0, 252.0, 254.0]

Or if you don't need load balancing:

# This sends the fold_package function for you!
results = mec.map(fold_package, range(128))

Let us know if you run into other problems.

Cheers,

Brian

On Mon, Feb 25, 2008 at 7:44 PM, Alexandre Gillet <gillet@scripps.edu> wrote:
> Hi,
>
>  I just started using ipython1 do to distribute job on multiple cpu.  I
>  am having some issue and I am not sure how it works.
>  I want to pass a function to be run by each task on each client.
>  In the following code, the function fold_package need to be run on each
>  client.
>
>  packages_list=[ '3114', '3115','3116']
>  # create a  remote  controller instance
>  rc = kernel.RemoteController(('127.0.0.1',10105))
>  # create task controller instance
>  tc = kernel.TaskController(('127.0.0.1', 10113))
>  # commands won't block by default
>  rc.block = False
>  # get id of available engine
>  engines_id = rc.getIDs()
>  # process the list of packages by dispatching them to different computer
>  # create the task list
>  tasks = [kernel.Task("fold_package(%s)"%t) for t in packages_list]
>  # test task controller
>  taskIDs = [tc.run(t) for t in tasks]
>
>
>  when I run that code I get:
>  NameError: name 'fold_package' is not defined
>
>  My questions are;
>  How do you pass a function define in my script to the client engine?
>  Or Do I have to create a package that will contains my function and
>  installed it on each client?
>
>  Thanks for any advices and answers.
>  Alex
>
>  --
>   o Alexandre Gillet    Ph.D.           email: gillet@scripps.edu
>  /  The Scripps Research Institute,
>  o  Dept. Molecular Biology,  MB-5,
>  \  10550  North Torrey Pines Road,
>   o La Jolla,  CA 92037-1000,  USA.
>  /  tel: (858) 784-2053
>  o  fax: (858) 784-2860
>     web: http://mgl.scripps.edu/projects/tangible_models/
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